Page 26 - Electronics Starter Kit_EN
P. 26
The first condition:
0. 7 ≤ in the dark
≤ ( + )
·
If we considered = 0. 7 and LDR = 600KΩ
( 600 Ω + )
600 Ω
0. 7 ≤ 5 · , ≤ 3. 685 Ω
The second condition:
0. 7 > in the dark
> ( + )
·
If we considered = 0. 7 and LDR = 6KΩ
( 6 Ω + )
6 Ω
0. 7 > 5 · , > 36. 857 Ω
So 3. 685 Ω ≥ > 36. 857 Ω , but 3.685MΩ will not work, because it won’t give
enough current on the base to make the LED light up.
The third condition:
− 0.7 5 − 0.7
< , < , < 215 Ω
20µ 20µ
So 215 Ω > > 36. 857 Ω , thus, any value between 215KΩ and 36.857KΩ will
work.
4.6 Example Picture
25
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